WebPredict the geometry of the [CoCl4] 2 complex showing their hybridized orbitals. Expert's answer Tetrahedral dsp 2 Co: [Ar 3d 7 4s 2] Co 2+: [Ar 3d 7 4s 2] Need a fast expert's response? Submit order and get a quick answer at the best price for any assignment or question with DETAILED EXPLANATIONS! WebCorrect option is C) [Ni(CN) 4] 2− is a square planar geometry formed by dsp 2 hybridisation and not tetrahedral by sp3. [NiCl 4] 2−, there is Ni 2+ ion, However, in the presence of weak field Cl − ligands, NO pairing of d-electrons occurs. Therefore, Ni 2+ undergoes sp 3 hybridization to make bonds with Cl − ligands in tetrahedral ...
Predict the geometry of the [CoCl^4]^2 complex showing …
WebFeb 21, 2024 · It's probably a Jahn-Teller distortion. From the electron configuration of the atoms: "Cu": [Ar] 3d^10 4s^1 "Co": [Ar] 3d^7 4s^2 Take away two electrons and you have the +2 oxidation states for both: "Cu"^(2+): [Ar] 3d^9 4s^0 "Co"^(2+): [Ar] 3d^7 4s^0 … WebInstructions to candidates y Do not open this examination paper until instructed to do so. y Answer all the questions. y For each question, choose the answer you consider to be the best and indicate your choice on the answer sheet provided. y The periodic table is provided for reference on page 2 of this examination paper. y The maximum mark ... thick 1
Solved Cobalt forms a tetrahedral complex with Clligands
WebSep 1, 2016 · In the case of Cu (II), it is a d 9 cation with a tetrahedral electronic … WebMay 10, 2024 · Tetrahedral geometry is a bit harder to visualize than square planar … WebApr 2, 2024 · 16.7k views asked Apr 2, 2024 in Chemistry by paayal (148k points) Which of the following has a square planar geometry? (a) [PtCl 4] 2– (b) [CoCl 4] 2– (c) [FeCl 4] 2– (d) [NiCl 4] 2– . (At. nos.: Fe = 26, Co = 27, Ni = 28, Pt = 78) coordination compounds & organometallics jee 1 Answer 0 votes answered Apr 2, 2024 by sanjaydas (89.7k points) thick 1020 trays